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[해답] 일반화학 7판 해답(사이플러스)

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작성일 21-10-06 23:31

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Download : [솔루션] 일반화학 7판 솔루션(사이.zip




기초과학인 일반화학 수업을 듣기 위한 솔루션입니다..^^ 확인해보세용~

Download : [솔루션] 일반화학 7판 솔루션(사이.zip( 76 )


(b) Express 802.6 in scientific notation.

1.23 (a) 15,200 (b) 0.0000000778

0.0095  9.5  103
Divide the N parts of the numbers in the usual way.
[해답] 일반화학 7판 해답(사이플러스) 입니다. Combining the above two steps:

Strategy: Lets express scientific notation as N  10n. When dividing numbers using scientific notation, divide the N parts of the numbers in the usual way. To come up with the correct exponent, n, we subtract the exponents.
(c) Express 0.000000621 in scientific notation.
Solution: Make sure that all numbers are expressed in scientific notation.
 8.5  103
0.749  7.49  101
For the above number expressed in scientific notation, n  6. The decimal place must be moved 6 places to the right to convert to nonscientific notation.
[솔루션] 일반화학 7판 솔루션(사이-4465_01_.gif [솔루션] 일반화학 7판 솔루션(사이-4465_02_.gif [솔루션] 일반화학 7판 솔루션(사이-4465_03_.gif [솔루션] 일반화학 7판 솔루션(사이-4465_04_.gif [솔루션] 일반화학 7판 솔루션(사이-4465_05_.gif




N  8.026



Solution: The decimal point must be moved two places to give N, a number between 1 and 10. In this case,
3.256  105  0.00003256


The usual practice is to express N as a number between 1 and 10. Since we must decrease N by a factor of 10 to express N between 1 and 10 (1.8), we must increase 10n by a factor of 10. The exponent, n, is increased by 1 from 3 to 2.

[해답] 일반화학 7판 해답(사이플러스)
(c) Subtraction using scientific notation.




1.24 (a) Express 3.256  105 in nonscientific notation.

Solution: The decimal point must be moved seven places to give N, a number between 1 and 10. In this case,


Let’s write 0.0095 in such a way that n  3. We have decreased 10n by 103, so we must increase N by 103. Move the decimal point 3 places to the right.
6.53  5.75  1.14

For the above number expressed in scientific notation, n  5. To convert to nonscientific notation, the decimal point must be moved 5 places to the left.
Solution: Write each quantity with the same exponent, n.
0.000000621  6.21  107
1.25 (a) 145.75  (2.3  101)  145.75  0.23  1.4598  102


Combining the above two steps:




Since 802.6 is a number greater than one, n is a positive integer. In this case, n  2.
(d) (1.0  104)  (9.9  106)  9.9  1010
Let’s write 850,000 in such a way that n  5. This means to move the decimal point five places to the left.

Strategy: Lets express scientific notation as N  10n. When adding numbers using scientific notation, we must write each quantity with the same exponent, n. We can then add the N parts of the numbers, keeping the exponent, n, the same.

Add the N parts of the numbers, keeping the exponent, n, the same.
(b)
설명

(c) (7.0  103)  (8.0  104)  (7.0  103)  (0.80  103)  6.2  103
[해답] 일반화학 7판 해답(사이플러스)


[솔루션] 일반화학 7판 솔루션(사이플러스) 입니다. [솔루션] 일반화학 7판 솔루션(사이플러스)
Strategy: Lets express scientific notation as N  10n. When subtracting numbers using scientific notation, we must write each quantity with the same exponent, n. We can then subtract the N parts of the numbers, keeping the exponent, n, the same.
1. Introduction




18.0  103
850,000  8.5  105
레포트 > 공학,기술계열



총 1장부터 22장까지의 해답이 있습니다.

18.0  103  1.8  102
9.5  103



Solution: Write each quantity with the same exponent, n.
6.03  106  6,030,000




(b) Division using scientific notation.

1.14  102  (8)  1.14  102  8  1.14  1010



653  6.53  102

기계, 공학, 화학, 일반, 솔루션





802.6  8.026  102

기초과학인 일반화학 수업을 듣기 위한 해답입니다.
Since 0.749 is a number less than one, n is a negative integer. In this case, n  1.




순서

Since 0.000000621 is a number less than one, n is a negative integer. In this case, n  7.
1.26 (a) Addition using scientific notation.
Combining the above two steps:


1장의 solution 부분을 발췌했습니다.
N  6.21
Subtract the exponents, n.


(b) Express 6.03  106 in nonscientific notation.
다. 총 1장부터 22장까지의 솔루션이 있습니다.
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